# -*- coding: utf-8 -*- import asyncio import random import aiohttp import time import sys from bs4 import BeautifulSoup import re import aiofiles import urllib.parse import argparse from colorama import init, Fore from search import Bing,Baidu import openpyxl import ssl from tool.read_csv import CSVReader start = time.time() def printascii(): # 初始化 init() # 设置颜色 print(Fore.GREEN + r''' ____ _ / ___| ___ __ _ _ __ ___| |__ ___ _ __ \___ \ / _ \/ _` | '__/ __| '_ \ / _ \ '__| ___) | __/ (_| | | | (__| | | | __/ | |____/ \___|\__,_|_| \___|_| |_|\___|_| ''' + Fore.RESET) # 天欣安全实验室 def writeExcel(titles, links,ws): infos = list(zip(titles, links)) for row in infos: ws.append(row) def create_sheet_and_write(wb, engine, keywords, num, title): ws = wb.create_sheet(title=title) result = engine(keywords, num) writeExcel(result[0], result[1], ws) def excel_text2url(link_url): #如果函数内部没有进行异步操作,使用 async 并不会对性能或功能产生实际影响。 '''把一个网址字符串转换为 Excel公式,使其可以点击直接转跳''' return f'=HYPERLINK("{link_url}","{link_url}")' # 遍历所有工作表,并将第二列的所有数据传递给 excel_text2url 函数重新赋值 def update_hyperlinks(wb): for sheet in wb.worksheets: # 遍历每一个工作表 for row in sheet.iter_rows(min_row=1, max_row=sheet.max_row, min_col=2, max_col=2): # 遍历第二列 for cell in row: if cell.value: # 检查单元格是否有内容 cell.value = excel_text2url(cell.value) # 将网址转换为超链接公式 else: break def commend(): parser = argparse.ArgumentParser(prog="Searcher", description='此工具用于对百度、必应和谷歌搜索的协程爬取--天欣安全实验室', usage='please read -h') parser.add_argument("-k", type=str, help="搜索的关键词", nargs='+') # 添加一个positional arguments,叫a,读取类型为int(默认是字符串) parser.add_argument("-p", type=str, help="需要搜索页数,默认为5,支持范围搜索,例如搜索从第2页到第五页的参数为 2:5", default='5') parser.add_argument("-m", type=str, help="使用的搜索引擎:百度:bd,必应:bin,谷歌:goo 不填写默认使用全部", default='all',nargs='+') # parser.add_argument("-t", '--task', type=int, help="设置的线程,默认为8", default=8) parser.exit_on_error = False args = parser.parse_args() if len(sys.argv) == 1: printascii() parser.print_help() sys.exit() return args def search_company_info(company_name_arg, num): keywords = company_name_arg # for key in keyword: # keywords = keywords + key + " " keywords = keywords.strip() result = Bing.bing_main(keywords, num) # for 循环 遍历 result[0] 和 result[1] data_list =[] for i in range(len(result[0])): title= result[0][i] url = result[1][i] print(f"必应搜索爬取结果为,title:{title}, url:{url}") if re.match(r"^https://aiqicha.baidu.com/company_detail_.*|https://www.qcc.com/firm/.*|https://www.tianyancha.com/company/.*", url): data_list.append([title, url]) return data_list def filter_company_sites(urls): # urls https://www.tianyancha.com/company/5226478758 # url:https://aiqicha.baidu.com/company_detail_26602790857925 # url:https://www.qcc.com/firm/05b449eb5cc417d0f97c14104051f5c0.html # 匹配 前缀https://aiqicha.baidu.com/company_detail_*,https://www.qcc.com/firm/*.html,https://www.tianyancha.com/company/5226478758* filtered_urls = [url for url in urls if re.match(r"^https://aiqicha.baidu.com/company_detail_.*|https://www.qcc.com/firm/.*|https://www.tianyancha.com/company/.*", url)] return filtered_urls def search_one_company(company_name_arg, num): keywords = company_name_arg # for key in keyword: # keywords = keywords + key + " " keywords = keywords.strip() print(f"您搜索的关键词为:{keywords}") wb = openpyxl.Workbook() # 删除默认创建的工作表(现在名为 "数据表1") wb.remove(wb['Sheet']) printascii() pattern = r"[\\/:\*\?\"<>|]" keyword = re.sub(pattern, "", keywords) create_sheet_and_write(wb, Bing.bing_main, keywords, num, "必应爬取结果") create_sheet_and_write(wb, Baidu.baidu_main, keywords, num, "百度爬取结果") # 将所有url变为超链接,点击即可打开转跳 update_hyperlinks(wb) wb.save(f'./{keyword}-{company_name_arg}.xlsx') print(Fore.GREEN + '总任务结束!' + Fore.RESET) end = time.time() print(Fore.RED + f'脚本总时间: {end - start:.2f}') if __name__ == '__main__': reader = CSVReader('data.csv') company_names = reader.read_column(0, has_header=False) print("所有数据:", company_names) i= 1 for company_name in company_names: sleep_time = 5 sleep_time += random.randint(1, 5) time.sleep(sleep_time) company_name += " 爱企查|企查查" data_list = search_company_info(company_name, '1') print(data_list) i=i+1 if i > 1: break